Views and the “with” rule#
Dependent pattern matching#
Since types can depend on values, the form of some arguments can be
determined by the value of others. For example, if we were to write
down the implicit length arguments to (++), we’d see that the form
of the length argument was determined by whether the vector was empty
or not:
(++) : Vect n a -> Vect m a -> Vect (n + m) a
(++) {n=Z} [] ys = ys
(++) {n=S k} (x :: xs) ys = x :: xs ++ ys
If n was a successor in the [] case, or zero in the ::
case, the definition would not be well typed.
The with rule — matching intermediate values#
Very often, we need to match on the result of an intermediate
computation. Idris provides a construct for this, the with
rule, inspired by views in Epigram [1], which takes account of
the fact that matching on a value in a dependently typed language can
affect what we know about the forms of other values. In its simplest
form, the with rule adds another argument to the function being
defined.
When this intermediate computation additionally appears in the type of the
function being defined, the with construct allows us to capture these
occurrences so that the observations made in the patterns will be reflected
in the type.
We have already seen a vector filter function. This time, we define it
using with as follows:
filter : (a -> Bool) -> Vect n a -> (p ** Vect p a)
filter p [] = ( _ ** [] )
filter p (x :: xs) with (filter p xs)
filter p (x :: xs) | ( _ ** xs' ) = if (p x) then ( _ ** x :: xs' ) else ( _ ** xs' )
Here, the with clause allows us to deconstruct the result of
filter p xs. The view refined argument pattern filter p (x ::
xs) goes beneath the with clause, followed by a vertical bar
|, followed by the deconstructed intermediate result ( _ ** xs'
). If the view refined argument pattern is unchanged from the
original function argument pattern, then the left side of | is
extraneous and may be omitted with an underscore _:
filter p (x :: xs) with (filter p xs)
_ | ( _ ** xs' ) = if (p x) then ( _ ** x :: xs' ) else ( _ ** xs' )
with clauses can also be nested:
foo : Int -> Int -> Bool
foo n m with (n + 1)
foo _ m | 2 with (m + 1)
foo _ _ | 2 | 3 = True
foo _ _ | 2 | _ = False
foo _ _ | _ = False
and left hand sides that are the same as their parent’s can be skipped by
using _ to focus on the patterns for the most local with. Meaning
that the above foo can be rewritten as follows:
foo : Int -> Int -> Bool
foo n m with (n + 1)
_ | 2 with (m + 1)
_ | 3 = True
_ | _ = False
_ | _ = False
Equivalently, multiple expressions separated by | can be can be deconstructed in one
with statement:
foo : Int -> Int -> Bool
foo n m with (n + 1) | (m + 1)
_ | 2 | 3 = True
_ | _ | _ = False
If the intermediate computation itself has a dependent type, then the
result can affect the forms of other arguments — we can learn the form
of one value by testing another. In these cases, view refined argument
patterns must be explicit. For example, a Nat is either even or
odd. If it is even it will be the sum of two equal Nat.
Otherwise, it is the sum of two equal Nat plus one:
data Parity : Nat -> Type where
Even : {n : _} -> Parity (n + n)
Odd : {n : _} -> Parity (S (n + n))
We say Parity is a view of Nat. It has a covering function
which tests whether it is even or odd and constructs the predicate
accordingly. Note that we’re going to need access to n at run time, so
although it’s an implicit argument, it has unrestricted multiplicity.
parity : (n:Nat) -> Parity n
We’ll come back to the definition of parity shortly. We can use it
to write a function which converts a natural number to a list of
binary digits (least significant first) as follows, using the with
rule:
natToBin : Nat -> List Bool
natToBin Z = Nil
natToBin k with (parity k)
natToBin (j + j) | Even = False :: natToBin j
natToBin (S (j + j)) | Odd = True :: natToBin j
The value of parity k affects the form of k, because the
result of parity k depends on k. So, as well as the patterns
for the result of the intermediate computation (Even and Odd)
right of the |, we also write how the results affect the other
patterns left of the |. That is:
When
parity kevaluates toEven, we can refine the original argumentkto a refined pattern(j + j)according toParity (n + n)from theEvenconstructor definition. So(j + j)replaceskon the left side of|, and theEvenconstructor appears on the right side. The natural numberjin the refined pattern can be used on the right side of the=sign.Otherwise, when
parity kevaluates toOdd, the original argumentkis refined toS (j + j)according toParity (S (n + n))from theOddconstructor definition, andOddnow appears on the right side of|, again with the natural numberjused on the right side of the=sign.
Note that there is a function in the patterns (+) and repeated
occurrences of j - this is allowed because another argument has
determined the form of these patterns.
Defining parity#
The definition of parity is a little tricky, and requires some knowledge of
theorem proving (see Section Theorem Proving), but for completeness, here
it is:
parity : (n : Nat) -> Parity n
parity Z = Even {n = Z}
parity (S Z) = Odd {n = Z}
parity (S (S k)) with (parity k)
parity (S (S (j + j))) | Even
= rewrite plusSuccRightSucc j j in Even {n = S j}
parity (S (S (S (j + j)))) | Odd
= rewrite plusSuccRightSucc j j in Odd {n = S j}
For full details on rewrite in particular, please refer to the theorem
proving tutorial, in Section Theorem Proving.